How do I rearrange this equation involving trig functions to solve for x?

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SUMMARY

The equation sin²(x)tan(x) = 1356 can be rearranged to solve for the unknown angle x by following a systematic approach. First, substitute tan(x) with sin(x)/cos(x) and express cos(x) as √(1 - sin²(x)). This leads to a sixth-order polynomial after squaring both sides. By substituting y = sin²(x), the equation simplifies to a third-order polynomial, which can then be solved for y to ultimately find the values of x.

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i am unsure about how to rearrange this equation so that I can solve for x an unknown angle. Please help.

we have:

sin^2 x(tan x)=1356

it is very simple I no but I just can't remember the way to go about solving this problem, especially because of the sin^2
 
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Follow the steps below:

1. [tex]tan(x) = \frac{sin(x)}{cos(x)}[/tex]
2. [tex]cos(x) = \sqrt{1 - sin^2(x)}[/tex]
3. take square on both size, and re-arrange the terms, you will get a 6th order polynomial
4. do a substitution [tex]y = sin^2(x)[/tex], then you will have a 3th order polynomial
5. solve the 3rd order polynomial for y...
6. as soon as you have y, you will get x... (make sure x is not a single value function of y)
 

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