How do I show that x^x->1 as x->0?
Try using log's to convert the exponentiation into a product.
I can't find a lower bound for xlog(x).
use l'hopital's rule.
if you have lim x log x then x log x is the same as [log x / (1 / x)]
Got it. Thanks.
You can also change it to what may be a more familiar limit by setting x=1/y.
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