- #1

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How do I show that x^x->1 as x->0?

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- Thread starter Treadstone 71
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- #1

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How do I show that x^x->1 as x->0?

- #2

Science Advisor

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Try using log's to convert the exponentiation into a product.

- #3

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I can't find a lower bound for xlog(x).

- #4

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use l'hopital's rule.

if you have lim x log x then x log x is the same as [log x / (1 / x)]

if you have lim x log x then x log x is the same as [log x / (1 / x)]

- #5

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Got it. Thanks.

- #6

Science Advisor

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You can also change it to what may be a more familiar limit by setting x=1/y.

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