How do I simplify a binomial division?

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    Binomial Division
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To simplify the binomial division of (v-4)/(5v+1), the process mirrors base-ten division. The first step is to divide v by 5v, yielding 1/5. Next, multiply 1/5 by (5v+1) and subtract this from (v-4), resulting in a remainder of -4.2, which can be expressed as a mixed number. The final simplified form is 1/5 - 21/(5(5v+1)).
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Homework Statement



(v-4)/(5v+1)

The Attempt at a Solution



I'm an engineering student, and I'm taking Differential Equations, but I can't remember how to do simple things like this.

A walk through explanation would be very much appreciated, I don't have a lot of time to spare.

The simplification I need to arrive at is = 1/5 - 21/(5*(5v+1))

The solution I've come up with is 1/5 - 42/(5v+1)

Can anyone help? Thanks
 
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The process is fundamentally the same as ordinary base-ten division using expanded form.

v vidided by 5v is 1/5. Multiply 1/5 by (5v+1), subtract from (v-4). Remainder is -4.2, but would be, "negative four and one fifth", in mixed number form.
My result seems to be (1/5)-4&(1/5)/(5v+1).
\frac{1}{5}-4\frac{1}{5}/(5v+1), seems TeX is not working.
\frac{}{}-\frac{}{}
 
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