How do I Solve 4z - 2conj(z) + i = 0?

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SUMMARY

The equation 4z - 2conj(z) + i = 0 has a confirmed solution of z = -i/6. The initial calculation mistakenly yielded z = -1/2*i due to an incorrect interpretation of the conjugate. By substituting z = -i/6 back into the equation, it verifies that this value satisfies the equation, while the calculator's output does not. This highlights the importance of careful handling of complex numbers and their conjugates in solving such equations.

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Homework Statement



hi

in trying to solve 4z - 2conj(z) + i = 0



Homework Equations





The Attempt at a Solution



the calculator spits out z = -1/2*i

i did 4(a+bi) - 2(a - bi) + i = 0

4a + 4bi - 2a + 2bi + i = 0

2a + 6bi + i = 0

i get z = -1/6*i

did i mess up somewhere? also, are there other solutions?

Thanks!
 
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You are right. The calculator is wrong. It looks like it solved 4z-2z+i=0.
 
Oftentimes it's difficult to get a solution, but simple to check. If z = -i/6, then
4z - 2\bar{z} + i
4(-i/6) -2(i/6) + i = 0
This shows that z = -i/6 is the solution to your equation. Similarly, you can show that what the calculator produced is not the solution.
 

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