How do I solve an equation with a variable in the numerator?

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Homework Help Overview

The discussion revolves around solving an absolute value equation involving a variable in the numerator of a fraction. The original poster expresses difficulty in separating the variable within the context of a quiz question.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method of multiplying both sides of the equation by the denominator as a potential approach. There are also suggestions to rewrite the fraction in a different form to facilitate solving.

Discussion Status

Some participants provide guidance on the validity of multiplying by the denominator and reiterate that such operations do not change the equality. There is an exploration of different scenarios, including cases where the variable is in the denominator.

Contextual Notes

The original poster mentions missing a quiz question due to confusion about handling the variable, indicating a potential gap in understanding the underlying principles of equation manipulation.

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Homework Statement



I just missed a 16-point question on a quiz because I didn't know how to separate the variable. It was an absolute value equation, but I just need to know how to deal with a variable in a fraction. Here's what it looked like:

Homework Equations



(5x+10)/2 = 20

The Attempt at a Solution


I tried multiplying everything by the denominator, but I'm not sure if or why that works. Any help would be greatly appreciated, thanks!
 
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Multiplying by denominator should work. You can do anything that doesn't change the equality - that means adding, subtracting, multiplying or dividing both sides of the equation by the same thing.

Or you could write the fraction as \frac {5x}{2} + \frac {10}{2}.
 
Thanks!
 
The easiest way is to multiply both sides of the equation by the denominator. The reason why this works is because it doesn't change the equality.

(5x+10)/2 = 20
5x+10 = 40
5x = 30
x = 6

Even if the variable was in the denominator, you can still solve for the variable using the same steps.

2/(5x+10) = 20
2 = 100x + 200
-198 = 100x
-198/100 = x
x = -99/50
 

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