How do i solve this physics problem that contains vectors

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SUMMARY

The discussion focuses on solving a physics problem involving vector addition and subtraction with two displacement vectors, A and B, each having a magnitude of 3.00. Vector A is positioned at a 30-degree angle from the positive X-axis, while Vector B lies along the Y-axis. The key to solving the problem is to decompose the vectors into their components, using the equations \(\vec{B}=3\hat{y}\) and \(\vec{A}=3\cos{30}\hat{x} + 3\sin{30}\hat{y}\). This method allows for the calculation of the resultant vectors for operations A+B, A-B, B-A, and A-2B.

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  • Understanding of vector components and their representation in Cartesian coordinates
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of vector addition and subtraction principles
  • Ability to perform calculations involving angles in degrees
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  • Practice vector decomposition in various physics problems
  • Learn about the Law of Cosines and its application in vector calculations
  • Explore graphical methods for vector addition and subtraction
  • Study the effects of changing angles on vector magnitudes and directions
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Students studying physics, particularly those focusing on mechanics and vector analysis, as well as educators looking for examples of vector operations in problem-solving contexts.

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Homework Statement


Each of the displacement vectors A and B have a magnitude of 3.00.
Vector B lies on the y-axis and Vector A has a 30 degree angle from the positive X axis.

a) A+B
magnitude = ?
θ = ?

(b) A-B
magnitude = ?
θ= ? °

(c) B - A
magnitude =?
θ= ? °

(d) A - 2B
magnitude =?
θ= ? °


Homework Equations





The Attempt at a Solution



I really don't have a clue how to figure this out, any help would be great
 
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The idea is, when adding vectors, to separate them into their components, and then add those components to make the new vector. You know \vec{B}=3\hat{y}, and \vec{A}=3\cos{30}\hat{x} + 3\sin{30}\hat{y}, at least you should know that. So then, for example, A + B = 3\cos{30}\hat{x} + (3 + 3\sin{30})\hat{y}. Make sense? See where you can get using this method.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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