Converting Area to Volume: A Spherical Coordinate Approach

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SUMMARY

The discussion focuses on deriving the infinitesimal area element dA in spherical coordinates for a hemispherical surface with a radius of 61 m in a uniform electric field of 3 V/m. Participants emphasize the relationship between area and volume elements, specifically referencing the triple integral ∫∫∫r²dr sin(θ)dθ dφ used for spherical volume calculations. The conversation highlights the importance of understanding the conversion from area to volume in spherical coordinates, suggesting that the area element can be derived from first principles or looked up in reference materials.

PREREQUISITES
  • Spherical coordinates (r, θ, φ)
  • Understanding of electric flux (φ = ∫ E dA)
  • Triple integrals in calculus
  • Basic principles of electromagnetism
NEXT STEPS
  • Research the derivation of the area element in spherical coordinates
  • Study the relationship between area and volume elements in calculus
  • Explore applications of electric flux in various geometries
  • Learn about the implications of uniform electric fields on surfaces
USEFUL FOR

Students in physics or engineering courses, particularly those studying electromagnetism and calculus, will benefit from this discussion. It is also relevant for educators looking to enhance their teaching of spherical coordinates and electric field concepts.

brioches
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Homework Statement



A hemispherical surface of radius b = 61 m is fixed in a uniform electric field of magnitude E0 = 3 V/m as shown in the figure. The x-axis points out of the screen.

Enter the general expression for an infinitesimal area element dA in spherical coordinates (r, θ, φ) using n as your outward-pointing normal vector. In these coordinates θ is the polar angle (from the z-axis) and φ is the azimuthal angle (from the x-axis in the x-y plane).
Mcu4dpw.png

Homework Equations


φ(flux) = ∫ E dA

The Attempt at a Solution


I understand that we're supposed to be looking for a small piece of area, but I don't know what makes up that area. We had a triple integral last semester of ∫∫∫r2dr sin(θ)dθ dφ. Is that related? We used that to integrate the volume of a sphere. Is there a similar process one can use for area?
 

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I guess you can either look up the area element in spherical coordinates or work it out for yourself from first principles.
 
brioches said:
∫∫∫r2dr sin(θ)dθ dφ. Is that related?
Very much so. Suppose you had an area element dA for a shell radius r within the sphere. How would you turn it into a volume element? Compare that with the integrand above.
 

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