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**1.**

a and b are constant.

I need to find the values of a and b that will make the system a a)unique solution, b)no solution, and c)infinitely many solution.

4x - 2y = 9

ax + by = 6

I know how to do it for a one variable constant. Say instead of a and b there was a k, but i do not know what steps to take to solve for two variable constant.

a and b are constant.

I need to find the values of a and b that will make the system a a)unique solution, b)no solution, and c)infinitely many solution.

4x - 2y = 9

ax + by = 6

I know how to do it for a one variable constant. Say instead of a and b there was a k, but i do not know what steps to take to solve for two variable constant.

## Homework Equations

**3. I solve for infinitely many solution and i got a = 8/3 and b = 4/3.**

but I'm having problems on solving for no solution.

I tried to get the coefficients the same, but you cannot multiply it by any number to make it the same coefficient as the first equation. So, i just got a = 4 b = -2 from the equations. and that seems to work. i was wondering if that is correct to do.

For a unique solution, if i just plug in a = 4 and b = 2 that gives me two intersecting line. but i was wondering how do I actually solve it to get a unique solution. What are the steps?

but I'm having problems on solving for no solution.

I tried to get the coefficients the same, but you cannot multiply it by any number to make it the same coefficient as the first equation. So, i just got a = 4 b = -2 from the equations. and that seems to work. i was wondering if that is correct to do.

For a unique solution, if i just plug in a = 4 and b = 2 that gives me two intersecting line. but i was wondering how do I actually solve it to get a unique solution. What are the steps?