How Do I Solve y''+4y'+4y=2+3e^2x and Find Related Resources?

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SUMMARY

The discussion focuses on solving the differential equation y'' + 4y' + 4y = 2 + 3e^(2x). The first step involves establishing the characteristic equation for the homogeneous part, y'' + 4y' + 4y = 0, which reveals a repeated root. To address the non-homogeneous equation, the method of undetermined coefficients is recommended for finding the particular solution. Additionally, the user seeks resources related to Leeds University MATH1400 sheet 4 questions.

PREREQUISITES
  • Understanding of second-order linear differential equations
  • Familiarity with characteristic equations
  • Knowledge of the method of undetermined coefficients
  • Basic concepts of homogeneous and non-homogeneous equations
NEXT STEPS
  • Study the derivation and application of characteristic equations in differential equations
  • Learn the method of undetermined coefficients for solving non-homogeneous differential equations
  • Explore examples of repeated roots in second-order linear differential equations
  • Research additional resources for MATH1400 coursework at Leeds University
USEFUL FOR

Students studying differential equations, particularly those enrolled in MATH1400 at Leeds University, as well as educators and tutors seeking to provide additional resources and examples for solving second-order linear differential equations.

franky2727
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unfortunately i have lost a question paper which has questions like y''+y'+y=sinx or =e^2x or =X+2-4+e^2x or=2^-3x+5E^-5e etc etc, i have the questions and answers for the y''+y'+y=0 format questions but none of the non zero questions so my question is 2 fold

first of all how do i go about answering y''+4y'+4y=2+3e2x

and second of all has anyone got leeds university MATH1400 sheet 4 questions for this year and if not which is the responce I'm expecting has anyone got any ideas where i can find examples of questions like this? thanks
 
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You want to set up the "characteristic equation" for
y'' + 4y' + 4y = 0 first and solve this for the values of r which will give you the solutions y = e^(rx) for the homogeneous equation.

You will find that this has a repeated root. How do you handle that?

The next step will be to use something like the method of undetermined coefficients to find the "particular solution" for the non-homogenous equation you started with.
 

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