How do mass and density relate in iron blocks when volume changes?

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Homework Help Overview

The discussion revolves around the relationship between mass, volume, and density in iron blocks, particularly when the volume changes. The original poster seeks clarification on how these parameters interact, especially when volume is doubled.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the distinction between mass and density through examples. Some participants question the nature of the relationship, with one suggesting a link to intrinsic versus extrinsic properties. Another participant provides a mathematical explanation of density as a ratio of mass to volume, illustrating that doubling both mass and volume results in unchanged density.

Discussion Status

The discussion is exploring various interpretations of the relationship between mass, volume, and density. While some mathematical reasoning has been provided, there is an ongoing inquiry into the statistical mechanics perspective, indicating a productive direction without reaching a consensus.

Contextual Notes

There is a mention of statistical mechanics, suggesting that the discussion may involve advanced concepts related to the physical behavior of materials under different conditions. The original poster has requested examples to aid understanding, indicating a need for further clarification.

jaan
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a block of iron defined by parameters mass,volume and density.when volume is doubled,the mass is also doubled;but the density of doubled volume of iron block remains the same.how do you distinguish the parameters mass and density.give any example (may be 2 or 3),so that i can understand well
thank u for taking ur valuable time.
 
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The density is the RATIO between mass and volume, \rho_{1}=\frac{m_{1}}{V_{1}}
where \rho_{1} stands for density for the first block, m_{1},V_{1} mass and volume for block 1 respectively.
If we look at a block 2 with twice the mass of block 1, that is m_{2}= 2m_{1}, and doubled volume V_{2}=2V_{1}, the density of this block is:
\rho_{2}=\frac{m_{2}}{V_{2}}=\frac{2m_{1}}{2V_{1}}=\frac{m_{1}}{V_{1}}=\rho_{1}
that is, the densities of the blocks are equal.
 
iam speaking statistically

as per STATISTICAL MECHANICS APPLY UR idea and can u eloborate the physical situation.
thank u
 

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