How do parities add up in a two-body system in the shell model?

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Discussion Overview

The discussion centers on the concept of parity in a two-body system within the shell model of a nucleus. Participants explore how to determine the total parity when combining states of different angular momentum.

Discussion Character

  • Technical explanation

Main Points Raised

  • One participant expresses confusion about how to calculate the total parity for a system with a neutron in a d state (l=2) and another in a p state (l=1).
  • Another participant states that the parity for a state is given by (-1)^{l}, and suggests that the total parity can be calculated as the product of the individual parities.
  • A later reply confirms that parities are indeed multiplied.

Areas of Agreement / Disagreement

Participants generally agree that parities are multiplied, but the initial confusion about the calculation method indicates some uncertainty in the understanding of the concept.

Contextual Notes

The discussion does not clarify the assumptions or definitions related to parity calculations, nor does it resolve the initial confusion expressed by the first participant.

physics_fun
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I'm confused about how parities 'add up'.
(I'm using the shell model of a nucleus)
If you have e.g.a neutron in a d state (so l=2) and one in a p state (l=1), what is the parity of the total system? Do you have to multiply (+1*-1=-1?) or add the l values or something completely different?
 
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Hey
The parity [tex]\pi[/tex] for a state is [tex](-1)^{l}[/tex] The total parity is
[tex]\pi_{1}*\pi_{2}[/tex] or
[tex](-1)^{l_{1}+l_{2}}[/tex]
 
Thanks!:smile:
 
Yes, parities are multiplied.
 

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