Johnleprekan said:
In a rock tumbler, the stones collide with each other and break apart. Eventually they become smooth. I was thinking about exchange of energy like when billiard balls hit. When two billiard balls collide, they exchange their energy. It's a little different if they have different amounts of momentum. This makes me question how a rock tumbler works. Can someone explain what is it about rock tumbling that causes the rocks to break up when they collide?
When two objects collide and exchange energy and momentum, there must be a force involved - thats' how the energy and momentum is transferred.
For example, suppose I drive an automobile into a brick wall. Before the collision, the automobile is moving with some speed v. A very short time later, the automobile is at rest. Therefore, the wall has exerted a force on the automobile to decelerate it during that time, and (if I assume for simplicity that the force is constant) the force and the time are related as: [itex]F=P/\Delta T[/itex] where F is the force, P is the momentum the automobile started with and ΔT is the time it takes for the collision. The force is very large, and sheet metal deforms plastically, so when the wall exerts that force on the automobile it crushes the sheet metal and smashes the car.
When two billiard balls collide, the same thing happens, except that the momentum and hence the forces are much lower, and a billiard ball is tough enough that the forces aren't sufficient to physically damage it.
What happens in your rock tumbler is somewhere in between. The force at the moment of impact is large enough, and the stone is brittle enough, that impacts between large pieces may break them up; but as the pieces become smaller and the momentum and force is reduced, the stones don't break but instead any projecting irregularities are knocked off.