How Do Suncreams Absorb UV Radiation at the Atomic Level?

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Homework Help Overview

The discussion revolves around the atomic interactions within suncreams when they absorb ultraviolet (UV) radiation. Participants explore the mechanisms by which suncream components protect against UV damage at the atomic level, particularly focusing on electron energy levels and photon interactions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the excitation of electrons to higher energy levels upon UV photon absorption and question the details of this process. There is an exploration of how electrons return to lower energy levels and the nature of emitted photons during de-excitation.

Discussion Status

The conversation is ongoing, with participants providing clarifications and asking for further explanations about the processes involved. Some guidance has been offered regarding the distinction between photon and electron behavior, and there is an active engagement in understanding the de-excitation process.

Contextual Notes

One participant notes that the question is from a past exam, indicating a structured context for the discussion. There is also mention of specific marks related to understanding electron energy levels, highlighting the academic framework within which the discussion is occurring.

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Homework Statement


Scientists put a lot of effort into developing suncreams which absorb the damaging wavelength of ultraviolet radiation. Suggest what might be happening to the atoms within the suncream when they absorb ultraviolet photons.


Homework Equations


None. This is an explain question.


The Attempt at a Solution


I believe the photons are excited to higher energy levels.

^What more could I write to explain this?
 
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It sounds to me like you're supposed to be doing some research. Have you tried to dig up anything online?
 
No, it's a past exam question. One mark was obtained with what I had written about energy levels and the second mark says 'related to electron energy levels' which I don't know how to explain.

Surely, what I have written that photons are excited to different energy level is the same concept?
 
No, not really. Photons aren't excited to different energy levels, atomic electrons are. And you can be more detailed. Remember that UV photons are more energetic than visible photons, which is why they cause damage. So you've got a powerful UV photon coming into penetrate deep into your skin tissue. But you've protected yourself with this cream that somehow softens the blow. Let's think about how that could happen.

The UV photon slams into you and gets absorbed by an atom in the sunscreen. When this happens, an electron gets excited from the ground state to a high energy level (skipping some intermediate energy levels).

Can you briefly describe a deexcitation process in which the emitted photons are less energetic than the initial UV photon?
 
Thanks for the great explanation. It was very clear. Erm, I didn't quite understand the question, but I think you wanted me to explain the process when electrons fall back levels.

When the electrons de-excite, they emit photons corresponding to the change in energy levels. These photons are by definition traveling at [itex]3.00 \times 10^8 \ \mathrm{ms^{-1}}[/itex] and release light.

Is that correct? :confused:
 
Air said:
When the electrons de-excite, they emit photons corresponding to the change in energy levels.

Right, and if the UV photon promotes an atomic electron up several energy levels, can you think of a way that it could come back down by (perhaps more than one, hint hint) photons that are all less energetic than UV photons?
 

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