1. The problem statement, all variables and given/known data 1. The problem statement, all variables and given/known data A 373-kg boat is sailing 13.0 ° north of east at a speed of 2.00 m/s. 32.0 s later, it is sailing 33.0 ° north of east at a speed of 3.90 m/s. During this time, three forces act on the boat: a 33.1-N force directed 13.0 ° north of east (due to an auxiliary engine), a 22.9-N force directed 13.0 ° south of west (resistance due to the water), and Fw(due to the wind). Find the (a) the magnitude and (b) direction of the force Fw. Express the direction as an angle with respect to due east. 2. Relevant equations Force=ma Kinematic equations 3. The attempt at a solution 33.1N-22.9N=10.2N Narrowed down the forces as these two are facing the same direction M=373Kg V0=2.0m/s vx0=1.95m/s vy0=.450m/s v=3.9m/s vx=3.27m/s vy=2.13m/s theta1=13degrees theta2=33degrees I am not sure where to go from here. What is missing is x,y,a, and Force of wind. Can get x,y,a from breaking Force down into the x and y components and then use that to find F=ma for x=v0t+1/2at^2 but then I don't know if that is right and still don't know how to get the force of the wind... Is that the right direction to go in at least? Thanks for any help on this one.