How Do Two Point Charges Affect Potential Above a Grounded Conducting Plane?

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SUMMARY

The discussion focuses on calculating the electric potential V(x,y,z) above a grounded conducting plane due to two point charges, q1 and q2, positioned along a line normal to the plane. The participant confirms that the potential at any point above the conductor is the sum of the potentials from both real charges and their corresponding image charges. The formula for the potential from a single point charge is utilized, and the participant correctly identifies that the total potential must equal zero at the grounded plane (z=0). The approach involves using the expression q1/(4πε0) * 1/r, where r is defined in Cartesian coordinates as (x² + y² + z²)^(1/2).

PREREQUISITES
  • Understanding of electrostatics and electric potential
  • Familiarity with the concept of image charges in electrostatics
  • Knowledge of Cartesian coordinates and their application in physics
  • Proficiency in using the formula for the potential of a point charge
NEXT STEPS
  • Study the method of image charges in greater detail
  • Learn how to derive the potential for multiple point charges
  • Explore the implications of grounded conductors in electrostatic problems
  • Investigate the mathematical techniques for solving potential problems in three dimensions
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in advanced concepts of electric potential and grounded conductors.

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Homework Statement



Two point charges q1 and q2 are located on a straight line normal to a grounded (V=0) conducting plane. Choosing the z axis to go through the charges, q1 is at a distance z1 above the conductor, and q2 is at a distance z2.

Find the potential V(x,y,z) everywhere above the conductor.


Homework Equations





The Attempt at a Solution



I know the formula for the potential of 1 point charge in open space. I can also use image charges to define the potential at a point V(x,y,z > 0). But for two charges, would the potential at any point be the sum of the individual potentials?
 
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Yes, the potential at a point (x,y,z > 0) is the sum of the potentials due to the two real and two virtual charges. Otherwise how would you ever get the potential to be zero at z=0?
 
So as of now, my answer is

q1/(4pi e0) * 1/r [from (z-d) to (z+d)]

and in cartesian coordinates, r is (x^2 + y^2 + z^2)^1/2

and i would just sum this up with the same process except for q2?
 

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