1. Mar 21, 2010 #1

   Luongo

   

   ie: in the figure theta 3 i got i want theta 2 what formula would i use

    

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   Luongo, Mar 21, 2010
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3. Mar 21, 2010 #2

   Luongo

   

   
   help please

    

   Luongo, Mar 21, 2010
4. Mar 21, 2010 #3

   Stonebridge

   

   I think it's th2=th1+th3-180

    

   Stonebridge, Mar 21, 2010
5. Mar 21, 2010 #4

   D H

   

   Staff Emeritus

   Science Advisor

   Insights Author

   There isn't enough information to tell.

    

   D H, Mar 21, 2010
6. Mar 22, 2010 #5

   Stonebridge

   

   
   
   It's basic geometry.
   Assuming the line I've drawn is parallel to the x axis
   
   th2 = th3 -th
   and
   th = 180 - th1
   Therefore
   th2 = th1 + th3 - 180

    

   Stonebridge, Mar 22, 2010

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