How Do You Calculate the Y Component of Velocity for an Arrow Shot at an Angle?

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SUMMARY

The calculation of the y component of velocity for an arrow shot at an angle of 59.4 degrees with an initial speed of 20.9 m/s involves using the equation V3 = Vo*sin(θ) - g*t. Here, Vo represents the initial velocity, θ is the launch angle, g is the acceleration due to gravity (9.8 m/s²), and t is the time in seconds. After substituting the values, the correct calculation for the y component at 3 seconds yields a result of approximately 1.5 m/s.

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  • Basic grasp of gravitational acceleration (9.8 m/s²)
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Homework Statement


An arrow is shot into the air at an angle of 59.4degrees above the horizontal with a speed of 20.9 m/s.

(a) What are the x and y components of the velocity of the arrow 3 s after it leaves the bowstring?


Homework Equations



v(o)sin(theta)t+1/2(a)(t^2)

The Attempt at a Solution


I know the x is just trig and ends up being 10.6 but i don't understand how to find the y component. I thought you just used the above equation and plugged 3 in for t and -9.8 for a since its going down. I did that and I got the wrong answer. Any help would be much appreciated. Thanks a lot
 
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Observe that the Vy (with positive up) is continually slowed by gravity.

Vt = Vo - g*t

or

V3 = Vo*sinθ - g*3

As you noted you have the x component already, so ...
 

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