How Do Wave Velocities and Frequencies Change in a Compound Wire System?

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Homework Help Overview

The problem involves a compound wire system consisting of an aluminium wire and a steel wire, where transverse waves are generated. The discussion focuses on the velocities of the waves in each wire, the relationship between frequency and the number of half-wavelengths, and the implications of the physical properties of the materials involved.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the velocities of waves in the aluminium and steel wires, questioning how to express these in terms of given parameters. There is exploration of the relationship between frequency and half-wavelengths, with some participants attempting to derive expressions based on the physical properties of the wires.

Discussion Status

Several participants are actively engaging with the problem, sharing insights and clarifying concepts. There is a recognition that the frequency must be consistent across the compound wire, leading to discussions about the implications for the number of half-wavelengths in each segment. Some participants are exploring numerical relationships between n1 and n2, while others are questioning assumptions and definitions.

Contextual Notes

Participants note that the problem involves specific values for lengths, densities, and mass, which may influence their calculations. There is an emphasis on finding the lowest frequency standing wave while ensuring that the joint between the wires acts as a node.

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Homework Statement



(a) An aluminium wire of length L1, cross-sectional area A and density ρ1 is connected to
a steel wire with the same cross-sectional area and density ρ2. This compound wire,
loaded with a block of mass m, is arranged as shown below so that the distance between
the joint and the supporting pulley is L2. Transverse waves are set up on the wire by using
an external source of variable frequency.(i) What are the velocities of the waves on the aluminium, v1, and steel wires, v2?

(ii) If we require that the joint is a node find the frequency of the wave on each part of the
wire in terms of the number of half wavelengths on that part of the wire, n1 on the
aluminium and n2 on the steel wires.

(iii) Given that L1 = 60.0 cm, L2 = 86.6 cm, ρ1 = 2.60 g cm-3, ρ2 = 7.86 g cm-3, A = 1:00 x
10-2 cm2 and m = 10.0 kg how many half-wavelengths are there on each part of the wire
for the lowest frequency standing wave such that the joint is a node?

(iv) What is the frequency of this vibration?

[Hint: In (a) (i) and i) the expressions should be in terms of in terms of the area A,
densities ρ1 and ρ2, the lengths L1 and L2, the number of half-wavelengths n1 and n2,mass
of the block m, and g the acceleration due to gravity.]

Homework Equations


\mu=A*\rho1
where \mu is the linear mass density

V=\sqrt{(F)/\mu}
where V is velocity
f1=\frac{Vn}{2L}

The Attempt at a Solution



i) using the first equation for velocity I get: V1=\sqrt{(mg)/A\rho1} and the same for V2

ii)I then plug into the second and get:
f1=\frac{n1}{2L1}\sqrt{\frac{mg}{A\rho}} with the same for f2

iii) This is where I run into problems:

For aluminium: f_low= f1=f1=\frac{V}{2L} because the largest wavelength is going to be 2L
therefore I get f1=\frac{V}{2L}=f1=\frac{Vn}{2L}
so n1=n2=1. Irrespective of the numbers they give us. This isn't right is it?

Homework Statement


Homework Equations


The Attempt at a Solution

 
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gboff21 said:
iii) This is where I run into problems:

For aluminium: f_low= f1=f1=\frac{V}{2L} because the largest wavelength is going to be 2L
therefore I get f1=\frac{V}{2L}=f1=\frac{Vn}{2L}
so n1=n2=1. Irrespective of the numbers they give us. This isn't right is it?
No, it isn't.

Hint: for something to be vibrating at some frequency, what is true about the frequency of vibration at different parts of the object?
 
Hi Redbelly

I know this thread is a year old but I'm working on the same problem at the moment. Does your hint mean that the frequency of vibration is the same throughout the wire regardless of the fact that it is a compound wire? So you can set f1=f2 and work out n1 in terms of n2 but how can you then work out what n1 and n2 is?

Thanks
 
dbatten said:
Hi Redbelly

I know this thread is a year old but I'm working on the same problem at the moment. Does your hint mean that the frequency of vibration is the same throughout the wire regardless of the fact that it is a compound wire? So you can set f1=f2 and work out n1 in terms of n2...
Yes, correct.
... but how can you then work out what n1 and n2 is?
They want the lowest possible (nonzero) frequency, so n1 and n2 must be as small as possible, but not zero.
 
Redbelly98 said:
Yes, correct.

They want the lowest possible (nonzero) frequency, so n1 and n2 must be as small as possible, but not zero.

Ok so I worked out that n1 is roughly 2.5n2 using the data given so can I just let n1 = 2 and n2 equal 5?
 
dbatten said:
Ok so I worked out that n1 is roughly 2.5n2 using the data given so can I just let n1 = 2 and n2 equal 5?
I think you have it backwards somewhere but yes, that is the idea.
 
Redbelly98 said:
I think you have it backwards somewhere but yes, that is the idea.

Oh yes I got it the wrong way around. n2 = 2.5n1. Thanks for your help
 
On a related note, just to make sure I have the concept: Each part of the 'string' would have a different wavelength due to the differing velocities v=SQRT(mg/Aρ), with ρ being different for each, right? Only the frequency would necessarily be constant?
 
NotACrook said:
On a related note, just to make sure I have the concept: Each part of the 'string' would have a different wavelength due to the differing velocities v=SQRT(mg/Aρ), with ρ being different for each, right? Only the frequency would necessarily be constant?
Yes, correct.
 

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