- #1

3psilon

- 1

- 0

## Homework Statement

1) an aluminium wire, of length L1 = 60.0 cm, cross sectional area 1.00 x 10^-2 cm^2, and density 2.60 g/cm^3, is joined to a steel wire of length L2, of density 7.80 g/cm^3 and the same cross sectional area. The compound wire, loaded with a block of mass m = 10.0 kg, is arranged so that the distance L2 from the joint to the supporting pulley is 86.6 cm. Transverse waves are set up in the wave using an external source of variable

a) find the lowest frequency of excitation for which standing waves are observed such that the joint in the wire is a node

b) How many nodes are observed at this frequency?

## Homework Equations

f1= 1/2L * √(T/mu)

## The Attempt at a Solution

So far, I know to find tension by basic Ft=Fg

I'm having trouble understanding the theory of it, there will be discontinuity because the change in linear density, but how can I account for that? Also, if there is a node where the lin. density changes, is the discontinuity relevant?

i also tried using percents for my linear density, i.e. 1.466 m = total length of the wire to the pulley, so then 41% of the wire is made up of aluminium, so the linear density could be written as mu = mualuminium + musteel, with adjusted linear density based on the percent

Last edited: