MHB How Do We Prove That 'P' Doesn't Vary for Different Free Variables?

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The discussion centers on understanding why a particular solution 'P' for the equation Ax=b does not vary with different free variable values. It is clarified that while 'P' does change with different choices of free variables, the overall set of solutions remains consistent regardless of the particular solution selected. The relationship between the null space and particular solutions is emphasized, illustrating that any particular solution can be expressed as a combination of the null space and a fixed vector. Thus, the choice of a particular solution does not affect the complete solution set. This highlights the stability of the solution space in linear algebra.
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I am studying Introduction to linear Algebra by Gilbert Strang while calculating the particular solution P for $Ax=b$,he made the free variables $0$ to calculate the particular solution and said that P along with linear combinations of null space solutions make up the complete set.
I understood that particular solution is 'particular' because there is only one solution to system of equation but how do we prove that 'P' doesn't vary for different free variable ( I mean other than $0$)??​
 
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Re: particular sollution for Ax=b

mathworker said:
how do we prove that 'P' doesn't vary for different free variable ( I mean other than $0$)??
A particular solution definitely varies with the choice of values of free variables because these values are a part of a solution. But the set of all solutions to the system does not depend on the choice of a particular solution.

There is the following fact. Let $L$ be a linear subspace and let $v$ be a particular vector (not necesarily in $L$). If $v'\in L+v$, then $L+v=L+v'$. Indeed, suppose that $v'=u+v$ where $u\in L$. Then an arbitrary vector in $L+v$ has the form $w+v$ where $w\in L$. But $w+v=w+v+u-u=(w-u)+v'$ and $w-u\in L$. The fact that $L+v'\subseteq L+v$ is proved similarly.

Returning to the system of linear equations, $L$ is the null space of $A$ and $v,v'$ are particular solutions. The choice of a particular solution does not change the set of all solutions.
 
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