How Do You Apply Taylor Series to Find Terms for f(x) = ln(3+x)?

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SUMMARY

The discussion focuses on applying Taylor Series to the function f(x) = ln(3+x). The user is guided to rewrite the function as ln(3) + ln(1 + x/3) to utilize the standard Taylor series expansion for ln(1+x). The resulting Taylor series up to the x^3 term is ln(3) + (x/3) - (x^2/18) + (x^3/81). This method effectively demonstrates how to derive the polynomial approximation for ln(3+x) using substitution.

PREREQUISITES
  • Understanding of Taylor Series expansion
  • Familiarity with logarithmic functions, specifically ln(x)
  • Knowledge of substitution techniques in calculus
  • Basic algebra skills for manipulating polynomial expressions
NEXT STEPS
  • Study the Taylor Series expansion for ln(1+x) in detail
  • Practice deriving Taylor Series for other functions using substitution
  • Explore convergence and error analysis of Taylor Series approximations
  • Learn about higher-order derivatives and their role in Taylor Series
USEFUL FOR

Students studying calculus, particularly those focusing on series expansions, mathematicians, and educators teaching Taylor Series applications.

morbello
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ive got a question to ask I am working on taylor series and want to know

f(x)=In(3+x) and g(x)=In (1+x)

by writing

In(3+x)=In3+In(1+1/3x)
im asked to use substitution in one off the standard taylor series given in the course.to find about 0 for f

explicitly all terms up to term in x^3

im not sure were to start.

I have

x+1/3 x^2+1*2/3 x^3+1*2*3/3 x^4+...
 
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I think you forgot to provide the function you're trying to find its Taylor's polynomial.
 
the function is ln(3+x) but you are told to write it as ln3 + ln(1 + x/3)

I believe you just need the standard series of ln (1+x) but sub in x/3 for the x.

So you would end up with

ln3 + x/3 - (x^2)/18 + (x^3)/81
 

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