Taylor Series for f(x) = (1+x)^m

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SUMMARY

The Taylor Series for the function f(x) = (1+x)^m about x=0 is expressed as a summation: Σ (m choose k) * x^k, where k ranges from 0 to m for non-negative integers. The series terminates when m is a non-negative integer because the binomial coefficients become zero for k > m. Additionally, the first four non-zero terms of the series for (1+x)^(-1/2) can be derived using the general formula, yielding 1 - (1/2)x - (1/8)x^2 - (1/16)x^3.

PREREQUISITES
  • Understanding of Taylor Series expansion
  • Familiarity with binomial coefficients
  • Knowledge of real numbers and their properties
  • Basic calculus concepts, particularly derivatives
NEXT STEPS
  • Study the derivation of Taylor Series for various functions
  • Explore binomial series and their applications in calculus
  • Learn about the convergence of Taylor Series for different values of m
  • Investigate the use of Taylor Series in approximating functions
USEFUL FOR

Students studying calculus, mathematicians interested in series expansions, and educators teaching Taylor Series concepts.

Grew Gore

Homework Statement


i) What is the Taylor Series for f(x) = (1+x)^m about x=0 where m is a real number?
ii) Why does this binomial series terminate when m is a non-negative integer? A
iii) Can the result to (i) be used to find the first four non-zero terms of the series for (1+x)^(-1/2)


Homework Equations

The Attempt at a Solution


I started getting: 1 + mx + 1/2(m-1)mx^2 +1/6(m-2)(m-1)mx^3 +... but am unsure if this is right and how to go on from here.
 
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That looks correct for (i) although they may prefer you to use general summation notation rather than '+...'
Now do (ii). Hint: Which, if any, of the terms in the expansion you wrote as answer to (i) will be zero if m is a positive integer?
 

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