How Do You Calculate Average Acceleration in a Piston Cycle?

  • Thread starter Palladian1881
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In summary: The correct calculation would be a = 2 * .05 m / (.005s)^2 = 400 m/s2. Therefore, the average acceleration is 400 m/s2. In summary, the average acceleration between the start/stop point and the middle of the cycle is 400 m/s2, calculated using the formula d = .5a * t2 and solving for a.
  • #1
Palladian1881
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1. Homework Statement
The piston has a displacement of 10 cm and there are 50 cycles per second. Calculate the average acceleration that occurs between the start/stop point and the middle of the cycle. This value has to do with evenly accelerated movement. This can be described according to the formula d = .5a * t2.
To solve:
-Compute the average velocity using a full cycle.
-Calculate how long the piston needs to travel 5 cm from the top of the cycle to the middle, which will give us the value for t. Then use a = 2 * d / t2 to calculate the acceleration.

2. Homework Equations
d = .5a * t2
a = 2 * d / t2
v = d / t

3. The Attempt at a Solution
50 cycles per second = 1 cycle takes 20 milliseconds.
velocity = d / t
10 m/s = 20 cm / 50 ms (total cycle distance is 20cm because the displacement is 10cm)
How long the piston takes to travel 5 cm: t = 5 ms
//But why figure out how long 5 cm takes, when I'm supposed to be solving for the middle of the cycle, which is 10 cm?
//Solving for 5 cm:
a = 2 * d / t2
d = 5 cm = .05 m
t = 5 ms = .005 s
a = 2 * .05 m / .005s2 = 20 m/s2
//But this isn't the right answer... How does the value for t work if it's supposed to be in seconds squared instead of just seconds? Should I plug in .0052 instead of just .005? Help!
 
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  • #2
After a full cycle the piston is back where it started from. Displacement from its point of origin is zero. So what's its average velocity?

If a formula says the value is to be squared, then yes, when you plug in the value for the variable it is to be squared. The "value" of the variable includes its units, so if the formula calls for t2 and t is 5s, then t2 is going to be 25s^2.
 
  • #3
Palladian1881 said:
2. Homework Equations
d = .5a * t2
a = 2 * d / t2
Note that these equations should be:
d = (.5)a * t2
a = 2d/(t2)


Palladian1881 said:
//Solving for 5 cm:
a = 2 * d / t2
d = 5 cm = .05 m
t = 5 ms = .005 s
a = 2 * .05 m / .005s2 = 20 m/s2
//But this isn't the right answer... How does the value for t work if it's supposed to be in seconds squared instead of just seconds? Should I plug in .0052 instead of just .005? Help!


You forgot to square the value for t.
 

Related to How Do You Calculate Average Acceleration in a Piston Cycle?

1. What is acceleration and how is it calculated?

Acceleration is the rate of change of an object's velocity over time. It is calculated by dividing the change in velocity by the change in time. The formula for acceleration is a=(vf-vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

2. How do you solve for acceleration in a given problem?

To solve for acceleration, you need to know the values for final velocity, initial velocity, and time. Once you have those values, you can use the formula a=(vf-vi)/t to calculate the acceleration. Make sure to use the correct units for velocity (m/s) and time (s) to get the correct units for acceleration (m/s^2).

3. What is the difference between average acceleration and instantaneous acceleration?

Average acceleration is the overall change in velocity over a given time period, while instantaneous acceleration is the acceleration at a specific moment in time. Average acceleration is calculated using the average velocity over the entire time period, while instantaneous acceleration is calculated using the velocity at a specific point in time.

4. How does mass affect acceleration?

Mass and acceleration have an inverse relationship, meaning that as mass increases, acceleration decreases, and vice versa. This is described by Newton's second law of motion, which states that the force applied to an object is equal to its mass multiplied by its acceleration (F=ma).

5. How can acceleration be used in real-world applications?

Acceleration is a fundamental concept in physics and has many real-world applications. It is used in designing vehicles, such as cars and airplanes, to ensure they can accelerate and decelerate safely. In sports, acceleration is used to train athletes to increase their speed and agility. It is also used in space exploration to calculate the trajectories of spacecraft. Additionally, acceleration is used in medical devices, such as MRI machines, to create images of the body's internal structures.

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