How Do You Calculate Air Temperature from Echo Delay and Speed of Sound?

Moe_slow
Messages
33
Reaction score
0
i need some help with this question.

"Jim is walking in a field and screams...the wall is 300 meters away it takes 1.7 seconds for the sound to come back...wat is the temperature in the air."

so i tried it as:

V=d/t
...= 300m/0.85s
...= 353m/s

from there i think i have to use the speed of sound formula and isolate the 0.59t. and then divide by it. i keep on getting a different answer then the one in my textbook.
 
Physics news on Phys.org
Cair= 331.5 + (0.6 x theta)
353 = 331.5 + (0.6 x theta)
theta = (353 - 331.5)/0.6
theta = 35.8 ºC

It's hot!
Notice that I get this formula from wikipedia, I could be wrong since I never learned this. But I read the article and it seems to be correct.

See- http://en.wikipedia.org/wiki/Speed_of_sound
 
thanks its correct...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
2K
Replies
16
Views
3K
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 31 ·
2
Replies
31
Views
4K