How Do You Calculate Angular Frequency in Simple Harmonic Motion?

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SUMMARY

The discussion focuses on calculating the angular frequency of a horizontal plank attached to a spring in simple harmonic motion. The plank has a mass of 2.0 kg and a length of 1.0 m, with the spring constant set at 1000 N/m. The correct formula for angular frequency is derived as w = (k/m)^0.5, leading to w = (1000/2)^0.5, which simplifies to w = 22.36 rad/s. The problem also involves analyzing moments acting on the plank to ensure it remains horizontal during oscillations.

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  • Understanding of simple harmonic motion principles
  • Familiarity with angular frequency calculations
  • Knowledge of moment and torque concepts
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  • Study the derivation of angular frequency in simple harmonic motion
  • Learn about the relationship between mass, spring constant, and oscillation frequency
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Homework Statement


A horizontal plank (m = 2.0 kg, L = 1.0 m) is pivoted at one end. A spring. (k = 1000N/m) is attached at the other end find the angular frequence for small oscillations?

Homework Equations


w=(k/m)^0.e\5


The Attempt at a Solution



w= (1000/2)^0.5
i have no idea is this a pendulum problem i tried the w=(mgd/I)^0.5 and that also did not work. How do i go about this problem thanks
 
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Weight of the plank acts through the CG of the plank.Clock wise moment due to this is 0.5*2*g. If the plank remains horizontal ,anticlockwise moment due to reaction in the spring = F*1 = F = mg = 0.5*2*g. So the spring appears to be stretched by a mass of 1 kg. using this value find w.
 

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