How Do You Calculate Binding Energy with the Weizsacker Formula?

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The discussion focuses on calculating the binding energy of Nickel-58 using the Weizsacker formula. Participants are tasked with determining various energy components, including surface energy, Coulomb energy, symmetry energy, and total binding energy, using specific parameters provided by Enrico Fermi. There is confusion regarding the delta term in the formula, with one participant questioning the value of 33 MeV x A^-3/4 compared to a different value found on Wikipedia. The conversation emphasizes the importance of correctly applying the parameters to achieve accurate results. Clarification on the delta term is sought to ensure proper calculations.
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Homework Statement


For 58Ni:
B(AZX) = aVA - aAA^2/3 - aC[Z(Z-1)]A^-1/3 - aS[(N-Z)^2]/A + δ.
Using the parameter values given by Enrico Fermi (aV = 14 MeV, aA = 13 MeV, aC = 0.72 MeV, aS = 19 MeV, ∆ = 33 MeV · A-3/4), determine each term in the formula.

Calculate the magnitude of the surface energy.

Determine the magnitude of the Coulomb energy.

What is the magnitude of the symmetry energy?

What is the total binding energy according to the Weizsacker formula?

What is the binding energy of the nucleus using the table of atomic masses ?


The Attempt at a Solution


For Nickel:
A=58
Z=28
N=30

Using the given parameters I think it would be a simple plug in on each term to find the wanted energies. So I am not sure why it won't work.
 
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yes i believe they are just plug ins

i am just curious why is your delta term 33MeV x A^-3/4

i checked wiki it says 11MeV x A^-1/2
 

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