The discussion revolves around calculating the capacitance of a capacitor in an AC circuit where a resistor is connected in series. The circuit operates at a frequency of 50 Hz and has a phase difference of 30 degrees between the voltage and current.
The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been suggested regarding the relationships between voltage and current in the circuit, but no consensus or resolution has been reached.
Participants note the absence of maximum voltage and current values, which may affect their ability to calculate capacitance directly. The phase difference is also a point of confusion that remains unaddressed.
delsoo said:Homework Statement
a resistor of 1000 ohm is connected in series to a capacitor and ac supply of frquency 50hz, if the phase diffennce of voltage supplied and current of circuirt is 30 degree, what's the capacitance of capacitor? the V max and I max in not given , how to do this ? help please!
Homework Equations
The Attempt at a Solution
delsoo said:since the reacatance(X c ) =V max/ I max . i let r = 1000 ohm = resistance, Xc also = //2pI (f)(C) , so i got 1000=1/2pi (50) (c) , but i don't know where to sub the 30 degree..