How Do You Calculate Centripetal Acceleration in Terms of g?

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Homework Help Overview

The problem involves calculating the centripetal acceleration at a specific distance from the center of a centrifuge, expressed in terms of the acceleration due to gravity (g). The context is centered around rotational motion and the relationship between linear and angular quantities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to express the calculated centripetal acceleration in terms of g, with some attempting to clarify the meaning of this expression. There is a focus on understanding the conversion of numerical values into terms of g.

Discussion Status

Participants are actively engaging with the problem, exploring how to express their answers in terms of g. Some guidance has been provided regarding the method of dividing by g to achieve the desired expression, but there is no consensus on the correctness of specific numerical values presented.

Contextual Notes

There is a mention of confusion regarding the given parameters, specifically whether the provided value is velocity or frequency, which may affect the calculations. Additionally, participants are discussing the implications of using different values for g in their calculations.

tascja
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Homework Statement


Calculate the magnitude of the centripetal acceleration at 8.4 cm from the centre of the centrifuge when it is spinning at 6.0x10^4 rpm. Express your answer in terms of g (acceleration due to Earth's gravity.)


Homework Equations


Ac = v^2 /
r

The Attempt at a Solution


I know the solution i just don't understand what they are asking from me when they say:
Express your answer in terms of g (acceleration due to Earth's gravity
 
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tascja said:
I know the solution i just don't understand what they are asking from me when they say:
Express your answer in terms of g (acceleration due to Earth's gravity


For example if you got your answer as 19.62ms^-2 that would be the same as 2*9.81 and since 9.81 is g, the acceleration would be 2g.

So what you want to do is divide your answer by 'g' i.e. 9.81, and the resulting number would be in terms of g.
 
thank you! so if my answer was 1.5x10^14 m/s^2 it would then become 1.53x10^13g ?
 
That would be it depending on what value you use for 'g'
 
tascja said:
thank you! so if my answer was 1.5x10^14 m/s^2 it would then become 1.53x10^13g ?
Yes, but that number is not the correct value of the acceleration.
 
Oh! its not velocity that's given its frequency
 
so the actual answer would be
Ac = 4.3x10^13 m/s^2

and in terms of g
= 4.3x10^12g
 

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