How Do You Calculate Current in a Half-Full Gasoline Gauge?

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SUMMARY

The discussion focuses on calculating the current in a gasoline gauge when the tank is half-full. The gauge has a resistance of 10 ohms, with the tank's variable resistor ranging from 200 ohms (empty) to 30 ohms (full). To find the resistance at half-full, one must determine the midpoint of the resistance range, which is 115 ohms. Using Ohm's Law (V=IR), the current can then be calculated based on the voltage applied across the circuit.

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could anyone help me with this problem?

Homework Statement



An automobile gasoline gauge is shown schematically in Figure 27-61. The indicator (on the dashboard) has a resistance of 10 . The tank unit is a float connected to a variable resistor whose resistance varies linearly with the volume of gasoline. The resistance is 200 when the tank is empty and 30 when the tank is full.


*Find the current when the tank is half-full*

Homework Equations



V=IR

The Attempt at a Solution


the current when the tank is empty is 12=I*200. so i multiplied that by two to get the answer but it was incorrect. i also tried to plug 15 into the equation since it's half of thirty but that too was wrong
 

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First let's make a little chart to describe the variable resistor:

200 ohms ... tank empty
? ohms ... tank half-full
30 ohms ... tank full

What number should I replace those question marks with?
 

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