- #1

eprparadox

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## Homework Statement

An automobile tire is pumped up to a gauge pressure of ##2.0 \times 10^5 ## Pa when the temperature is 27◦ C. What is its gauge pressure after the car has been running on a hot day so that the tire temperature is 77◦ C? Assume that the volume remains fixed and take atmospheric pressure to be ##1.013 \times 10^5 ## Pa.

A. 1.6×10^5Pa

B. 2.6×10^5Pa

C. 3.6×10^5Pa

D. 5.9×10^5Pa

E. 7.9×10^5Pa

## Homework Equations

## \frac{P_1}{T_1} = \frac{P_2}{T_2} ##

## The Attempt at a Solution

I think you have to use absolute pressure and not gauge pressure so using the above equation, I got

[tex] \frac{2.0 \times 10^5 + 1.013 \times 10^5}{ 27 + 273} = \frac{x + 1.013 \times 10^5}{77 + 273} [/tex]

Solving for ## x ##, I get ##2.5 \times 10^5 Pa ##.

The answer given is A but I get closest to B.

Any thoughts on where I'm going wrong?