How do you calculate density of a vapor only vapor pressure and temp.

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SUMMARY

The discussion focuses on calculating the density of mercury vapor using its vapor pressure of 0.00169 mmHg at 24 degrees Celsius. The ideal gas law is identified as the appropriate method for determining the molar density of mercury vapor, expressed as n/V = P/RT. By substituting the vapor pressure and temperature into this equation, one can derive the number of moles per cubic meter and subsequently convert this to the number of mercury atoms using Avogadro's number. The realization that liters can be converted into cubic meters is crucial for accurate calculations.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of vapor pressure and its significance
  • Familiarity with Avogadro's number
  • Basic unit conversions between liters and cubic meters
NEXT STEPS
  • Study the ideal gas law in detail, focusing on its applications in real-world scenarios.
  • Research the significance of vapor pressure in various chemical contexts.
  • Learn about Avogadro's number and its role in converting moles to atoms.
  • Explore unit conversion techniques, particularly between liters and cubic meters.
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Chemists, physicists, and environmental scientists interested in vapor density calculations and the implications of mercury vapor exposure.

aleksbooker
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Hello all,

The question given is:

Mercury and many of its compounds are dangerous poisons if breathed, swallowed or even absorbed through the skin. The liquid metal has a vapor pressure of 0.00169mmHg at 24 degrees Celsius. If the air in a small room is saturated with mercury vapor, how many atoms of mercury vapor occur per cubic meter?

I can't use Clausius-Clapeyron because I only have one pressure and one temperature to work with, and I can't use PV = nRT, because I don't know how many moles of mercury I have. If I arbitrarily increase the moles, I increase the volume just as quickly, which may not affect density, but either way I don't know the concentration of moles per liter. I even considered the pressure = force/area, but that's not relevant to volume.

I'm certain the fact that the air is saturated is somehow key, but I can't find anything in my textbook that seems to address this question. What am I missing?

Thanks,
Aleks
 
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Hi Aleks. Welcome to Physics Forums!

You can use the ideal gas law. You first need to find out how many moles of mercury there are in each cubic meter. From the ideal gas law, the molar density is \frac{n}{V}=\frac{P}{RT}. This has units of moles per cubic meter. You then multiply by Avagado's number to get the number of atoms per cubic meter. In this equation, P is the vapor pressure at 24 (room temperature) and you use T = 273+24.

Chet
 
Thanks, Chet!

It took some fishing, but I figured it out. I didn't consider that liters could be converted into cubic meters.
 

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