How Do You Calculate Displacement and Acceleration in a Kinematics Car Problem?

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SUMMARY

The discussion focuses on calculating displacement and acceleration in a kinematics problem involving a car's motion. The car accelerates at 3.0 m/s² for 5.0 seconds, resulting in a final velocity of 15 m/s. During the last 8.0 seconds of braking, the acceleration is determined to be -1.9 m/s², correcting an earlier miscalculation of -1.7 m/s². The total displacement calculated is 403.1 meters, derived from three segments of motion.

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This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding motion dynamics in kinematics problems.

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A car starts from rest heading due east. It first accelerates at 3.0m/s^2 for 5.0s and then continues without further acceleration for 20.0s. It then brakes for 8.0s in coming to rest. (a) What is the car's velocity after the first 5.0 seconds? (b) What is the car's acceleration over the last 8.0s interval? (c) What is the total displacement?






The Attempt at a Solution



This is what i got: a) vf=vi+at
=0(3)(5)
vf=15m/s

b) vf=vi+at
0=15+a(8)
-15=a(8)
a=-1.7m/s^2

c) d1=37.5m
d2=300m
d3=65.6m
dtot=403.1m
 
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miamiheat5 said:
This is what i got: a) vf=vi+at
=0(3)(5)
vf=15m/s

Correct.

b) vf=vi+at
0=15+a(8)
-15=a(8)
a=-1.7m/s^2
15/8 is not 1.7

c) d1=37.5m
d2=300m
d3=65.6m
dtot=403.1m

d3 would change based on the answer to b.
 
ya it should be -1.9
 

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