How Do You Calculate Electrical Current Density with Complex Integrals?

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SUMMARY

The discussion focuses on calculating electrical current density using complex integrals, specifically the formula \(\sigma = \frac{{e^{2}}}{4\pi^{3}} \int{\left( -\frac{\partial f}{\partial \varepsilon} \right)\tau \cdot \mathbf{v}\cdot \mathbf{v}}\,dk\). The Fermi function \(f\) is defined as \(f = \frac{1}{\exp \left( \frac{\varepsilon - \mu}{{k_{B}}T} \right) + 1}\), with \(\varepsilon = \frac{{\hbar^{2}}{k^{2}}}{2m}\) and \(v = \frac{\partial \varepsilon}{\partial k}\). The main challenge discussed is simplifying the integral involving exponential functions, particularly \(\int{\exp \left( \frac{\varepsilon + \mu}{{k_{B}}T} \right)}\,k^{2}dk\).

PREREQUISITES
  • Understanding of complex integrals in physics
  • Familiarity with the Fermi function and its properties
  • Knowledge of differentiation and integration techniques
  • Basic concepts of electrical current density in solid-state physics
NEXT STEPS
  • Study techniques for solving integrals involving exponential functions
  • Learn about the application of the chain rule in calculus
  • Explore partial integration methods for complex integrals
  • Research the physical significance of electrical current density in semiconductor physics
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Students and researchers in physics, particularly those studying solid-state physics, electrical engineering, or anyone working with complex integrals in the context of electrical current density calculations.

Denver Dang
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Homework Statement


Hi.

I'm having some trouble calculating the electrical current density, which in my case is given by:

[tex]\sigma =\frac{{{e}^{2}}}{4{{\pi }^{3}}}\int{\left( -\frac{\partial f}{\partial \varepsilon } \right)\tau \cdot \mathbf{v}\cdot \mathbf{v}}\,dk[/tex]

Homework Equations



Lets assume that [itex]\tau[/itex] is constant, and that:

[tex]f=\frac{1}{\exp \left( \frac{\varepsilon -\mu }{{{k}_{B}}T} \right)+1},[/tex]
the Fermi function.
And that:
[tex]\varepsilon =\frac{{{\hbar }^{2}}{{k}^{2}}}{2m}[/tex]
and
[tex]v=\frac{\partial \varepsilon }{\partial k}[/tex]

The Attempt at a Solution



Then, how am I supposed to do this integral ?
Exponential functions are so annoying if they are not alone.

I am supposed to end up with a value/number, but I really can't see how this is doable when I have all these exponential functions. When you differentiate the Fermi function, before putting it inside the integral, you get even more exponential functions.

So yes, I'm kinda lost here. So I was kinda hoping for someone who might be able to give a little hint :)Thanks in advance.
 
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Use the chain rule. You have [itex]v = \frac{1}{\hbar} \frac{\partial \epsilon}{\partial k}[/itex], so [tex]v dk = \frac{1}{\hbar} \frac{\partial \epsilon}{\partial k} dk = \frac{1}{\hbar} d \epsilon[/tex] After that, I have no idea. You can try partial integration, which let's you dodge the derivative, although I didn't actually do the calculation so I don't know if it gets easier.
 
Hmmm, I've actually narrowed it down to several integral, only one being hard, which is:

[tex]\int{\exp \left( \frac{\varepsilon +\mu }{{{k}_{B}}T} \right)}\,{{k}^{2}}dk,[/tex]
where epsilon is the energy given in my first post.

Any clever way to solve this now ?
 

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