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If a natural product was isolated and was found to have an enantiomeric excess (ee) of 84% what would be the percentages of each enatiomer in the mixture?
The calculation of enantiomer percentages from enantiomeric excess (ee) is straightforward. For an enantiomeric excess of 84%, the major enantiomer constitutes 92% of the mixture, while the minor enantiomer accounts for 8%. This is derived using the formula: Major isomer % = (100 + ee) / 2. Understanding the relationship between enantiomeric excess and the composition of enantiomers is crucial for accurate analysis in stereochemistry.
PREREQUISITESChemists, particularly organic chemists and pharmacologists, will benefit from this discussion as it provides essential insights into calculating enantiomer percentages and understanding their significance in chemical mixtures.
uorganic said:If a natural product was isolated and was found to have an enantiomeric excess (ee) of 84% what would be the percentages of each enatiomer in the mixture?