How Do You Calculate Force on a Water Jet Deflected by a Plate?

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SUMMARY

The discussion focuses on calculating the force exerted by a water jet deflected by a flat plate. The volumetric flow rate of water is given as 10 liters in 7 seconds, leading to a calculated flow rate (Q) of approximately 1.429 m³/s. The density of water at 20 degrees Celsius is 998.2 kg/m³, and the force equation is established as F = density * area of nozzle * velocity² * (1 - C*cos(theta)), with C set to 1 and theta at 90 degrees. However, the area of the nozzle remains unknown, which complicates the calculation of force.

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michael7777
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Homework Statement


A jet of water going through a nozzle is deflected by a flat plate. Get Q, Velocity, Force

The volumetric flow rate of water through the nozzle is 10 Litres in 7 seconds

The water temperature is 20 degrees celsius.
We are using a flat plate so theta = 90 degrees
Velocity coefficient C = 1

Homework Equations


Q (volume flow rate) = volume / time
Velocity = Q / area of nozzle
Force = density of water * Area of nozzle * velocity^2 * (1 - C*cos theta)

The Attempt at a Solution


Density of water at 20 degrees = 998.2 kg/m^3
Q = 0.01 / 7
Q = 1.429 (10^3) m^3/s

I don't know how to get area of nozzle

Using C = 1, theta = 90:
F = 1000 * area of nozzle * V^2
 
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michael7777 said:
A jet of water going through a nozzle is deflected by a flat plate. Get Q, Velocity, Force

The volumetric flow rate of water through the nozzle is 10 Litres in 7 seconds

I don't know how to get area of nozzle

Hi michael7777! :smile:

I agree with you … there isn't enough information. :confused:

(btw, another way of calculating it is force = rate of change of momentum = mass x velocity/time … but again, we don't know the velocity. :cry:)
 

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