How Do You Calculate Frictional Force on a Block?

AI Thread Summary
To calculate the frictional force on a 10-lb block subjected to a 3-lb horizontal force, the static friction coefficient (\mus) is 0.5 and the kinetic friction coefficient (\muk) is 0.4. The maximum static friction force required to move the block is calculated to be approximately 49.0 lb, or 22N. Since the applied force of 3-lb (about 1.4N) is less than this maximum, the frictional force equals the applied force. Thus, the frictional force acting on the block is 3-lb.
mdawg467
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Homework Statement


A 3-lb horizontal force is applied to a 10-lb block on a rough horizontal surface. The block is initially at rest. If \mus is 0.5 and the \muk is 0.4, the frictional force on the block is?


Homework Equations


FN=mg
Fk=\mukFN
Fs,max=\musFN


The Attempt at a Solution


I found \mus,max required to move the 10-lb block was 49.0 lb/ms^2..or approximately 22N.

Since the force being applied is 3-lb, or approximately 1.4N, then the frictional force must be equal to the force being applied correct?

Thanks.
 
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mdawg467 said:

Homework Statement


A 3-lb horizontal force is applied to a 10-lb block on a rough horizontal surface. The block is initially at rest. If \mus is 0.5 and the \muk is 0.4, the frictional force on the block is?


Homework Equations


FN=mg
Fk=\mukFN
Fs,max=\musFN


The Attempt at a Solution


I found \mus,max required to move the 10-lb block was 49.0 lb/ms^2..or approximately 22N.

Since the force being applied is 3-lb, or approximately 1.4N, then the frictional force must be equal to the force being applied correct?

Thanks.

Sounds good - especially in America where apparently the pound is a unit of Force, not a unit of mass.
 
Thank you!
Yeah only here in America haha..
 
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