Find force and coefficient of friction between 2 stacked blocks in motion

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SUMMARY

The discussion centers on calculating the force of friction and the minimum coefficient of friction between two stacked blocks when a force of 30N is applied to the bottom block. The acceleration of the system is determined to be 2 m/s². The relevant equations include Fnet = ma, muK = Fk/Fn, and mu s = Fs,max/Fn. The participants emphasize the importance of calculating the normal force (Fn) of the top block and applying the kinetic friction formula to find the required coefficient of friction.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of friction coefficients (muK and mu s)
  • Ability to calculate normal force (Fn) in a stacked block system
  • Familiarity with basic kinematics and acceleration concepts
NEXT STEPS
  • Calculate the normal force (Fn) for the 5kg block in the system
  • Apply the kinetic friction formula (muK = Fk/Fn) to find the coefficient of friction
  • Explore the implications of frictionless surfaces in block motion scenarios
  • Review concepts of static versus kinetic friction in multi-block systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and friction, as well as educators looking for practical examples of friction calculations in stacked block systems.

gabemarkus
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Homework Statement


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The surfaces of two blocks are roughened so that they do not slide against each other when a force of 30N is applied to the bottom block. 1.Find the force of friction between the two blocks. 2. Find the minimum coefficient of friction needed between the two blocks so that the top block does not move.

Homework Equations


Fnet = ma
muK = Fk/Fn
mu s = Fs,max/Fn

The Attempt at a Solution


I found the acceleration of the two block system, which is 2 m/s². I'm wondering if you have to find the Fn of the 5kg block then act as if it was moving 2m/s² by itself over the 10kg block then determine Fk from that and plug it into muK = Fk/Fn. Thanks for any help!
 
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Or, do you have to find the accelerations of the blocks separately at first?
 
gabemarkus said:

Homework Statement


View attachment 73930
The surfaces of two blocks are roughened so that they do not slide against each other when a force of 30N is applied to the bottom block. 1.Find the force of friction between the two blocks. 2. Find the minimum coefficient of friction needed between the two blocks so that the top block does not move.

Homework Equations


Fnet = ma
muK = Fk/Fn
mu s = Fs,max/Fn

The Attempt at a Solution


I found the acceleration of the two block system, which is 2 m/s². I'm wondering if you have to find the Fn of the 5kg block then act as if it was moving 2m/s² by itself over the 10kg block then determine Fk from that and plug it into muK = Fk/Fn. Thanks for any help!
Finding the acceleration of the system was the right first step. (I assume there's no friction between the lower block and the ground.) I'm not sure what you are suggesting as the next step. Why not apply it and post the working that results? That will be a lot clearer.
 

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