How Do You Calculate Image Size and Location with a Diverging Lens?

[Robin_oto]

okay the problem reads
-an object 3 cm tall is placed 16 cm in front of a diverging lens with a focal length of 24cm. Find the location and size of the image. What kind of image is it?



1/f = 1/d_i+1/d_o

h_i/h_o = d_i/d_o


I'm not to sure how to solve this i used the equation; 1/f = 1/d_i+1/d_o and solved for d_i, getting -48cm. then pluged it into the equation h_i/h_o = d_i/d_o, and got -9cm. It doesn't seem right to me because when i draw out the problem it shows the image as smaller then the actual size, not bigger. please help!

 

[ehild]

The focal length of a diverging lens should be taken negative: f=-24 cm

ehild