How Do You Calculate Impulse and Force in a Racquetball Collision?

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Homework Help Overview

The discussion revolves around calculating impulse and force in the context of a racquetball collision with a backboard. The original poster presents a scenario involving a hollow racquetball with specified mass and speeds before and after the collision.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate impulse and average force using momentum and acceleration formulas. Some participants question the signs of the velocities used in the calculations, while others seek clarification on the units of impulse and force.

Discussion Status

The discussion is active, with participants exploring different interpretations of the calculations. There is a focus on understanding the reasoning behind the signs of the velocities and the appropriate units for impulse and force. No consensus has been reached yet.

Contextual Notes

Participants are discussing the implications of negative velocity in the context of direction after the collision. There is also a concern regarding the correct units for impulse and force, indicating potential confusion in the calculations presented.

mememe1245
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Question
A 0.0420-kg hollow racquetball with an initial speed of 12.0 m/s collides with a backboard. It rebounds with a speed of 6.0 m/s.
a. Calculate the total impulse on the ball.
b. If the contact time lasts for 0.040 s, calculate the average force on the ball.

What I did on the test:
(A)Impulse=F x change in T=change in momentum(mass x velocity)

F= unknown, so use the formula, F=M x A

_________________________

Momentum=

P(momentum)= 0.0420kg x 6m/s

P= .252N

Therefore, the impulse on the ball is, .252kg. m/s.

****************************************************************

(B) F= Mass x Acceleration

change in Velocity= Acceleration x Time

Acceleration= change in Velocity/ Time

A= Velocity final - Velocity initial/ Time

A= 6m/s -12m/s/0.040s

A= -6m/s/0.040s

A= - 150 m/s^2

_____________

F= M x A

F= 0.042kg x (-150m/s^2)

F= -6.3 N
 
Last edited by a moderator:
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(-6) - 12 = -18
 
Chestermiller said:
(-6) - 12 = -18
Why is the "6" negative?
 
mememe1245 said:
Why is the "6" negative?
Because after it bounces off the wall it moves in the opposite direction.
 
Chestermiller said:
Because after it bounces off the wall it moves in the opposite direction.
Ohhh...Okay.
so, 18 x 0.0420kg
P = .756N?
 
mememe1245 said:
Ohhh...Okay.
so, 18 x 0.0420kg
P = .756N?
Are you sure about the units of P (if you indeed mean that P is the impulse of the force)?

Chet
 
Chestermiller said:
Are you sure about the units of P (if you indeed mean that P is the impulse of the force)?

Chet
Nm
 
mememe1245 said:
Nm
No. You're just guessing.

What are the units of mass? What are the units of velocity? What are the fundamental units of a Newton?

Chet
 

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