How Do You Calculate Lx and Ly Using Spherical Harmonics in Quantum Mechanics?

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SUMMARY

The discussion focuses on calculating the angular momentum operators Lx and Ly using spherical harmonics in quantum mechanics, specifically in the basis of functions Y^{±1}_{1}(θ, φ) and Y^{0}_{1}(θ, φ). The user seeks clarification on the correct method to derive the matrix elements for Lx and Ly, utilizing the formula (L_{x})_{n'n} = <ψ^{(n'-2)}_{1}|L_{x}|ψ^{(n-2)}_{1}>. It is confirmed that using the raising and lowering operators L+ and L- simplifies the calculations for these operators.

PREREQUISITES
  • Understanding of angular momentum operators in quantum mechanics
  • Familiarity with spherical harmonics Y^{m}_{l}(θ, φ)
  • Knowledge of matrix representation in quantum mechanics
  • Experience with raising and lowering operators L+ and L-
NEXT STEPS
  • Study the derivation of angular momentum operators in quantum mechanics
  • Learn about the properties and applications of spherical harmonics
  • Explore the use of raising and lowering operators in quantum mechanics
  • Investigate the matrix representation of quantum operators
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Quantum mechanics students, physicists working with angular momentum, and anyone interested in the mathematical formulation of quantum operators.

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Homework Statement


Obtain the angular momentum operators L_{x} and L_{y} in the basis of functions Y^{\pm1}_{1}(\theta,phi} and Y^{0}_{1}(\theta,phi}[/itex] in Lz representation<b>2. The attempt at a solution</b><br /> To calculate the matrices for the Lx and Ly operators, do i simply have to take the relevant spherical harmonics and apply Lx and Ly like this<br /> <br /> To form the Lx the terms are given for n&#039;n term of the matrix<br /> <br /> (L_{x})_{n&amp;#039;n} = &amp;lt;\psi^{(n&amp;#039;-2)}_{1}|L_{x}|\psi^{(n-2)}_{1}&amp;gt;<br /> <br /> from this i can determine the terms of the Lx matrix<br /> similarly for the Ly matrix?<br /> <br /> am i correct? Thanks for any help.
 
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It's easier to use the raising and lowering operators L+ and L-.
 

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