How Do You Calculate Mass and Density Using Dimensional Analysis?

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SUMMARY

The discussion focuses on calculating mass and density using dimensional analysis, specifically addressing three problems involving ethylene glycol, liquid density measurement, and dustfall conversion. The first problem calculates the mass of 417 mL of ethylene glycol with a density of 1.1 g/cm³, resulting in a mass of 458.7 grams. The second problem determines the density of a liquid by weighing a flask before and after filling it, yielding a density of 0.79 g/mL. The third problem converts dustfall from tons per square kilometer per month to milligrams per square meter per month, resulting in 3.501 x 1012 mg/m²/month. The relevant formula for these calculations is ρ = M/V (Density = Mass/Volume).

PREREQUISITES
  • Understanding of dimensional analysis
  • Familiarity with density calculations
  • Knowledge of unit conversions (e.g., tons to pounds, pounds to kilograms)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the principles of dimensional analysis in physics
  • Learn how to calculate density using various units
  • Practice unit conversion techniques for mass and volume
  • Explore real-world applications of density in fluid mechanics
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Students studying physics or chemistry, educators teaching dimensional analysis, and anyone needing to perform calculations involving mass and density in practical scenarios.

montagical
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Homework Statement


I have a few problems that I'm unsure how to proceed with...

1. Ethylene glycol, and antifreeze, has a density of 1.1 g/cm^3. What is the mass, in grams, of 417 mL of this liquid? 1 cm^3 = 1 mL

2. To determine the density of a liquid, a flask is weighed empty (108.6g) and again when filled with 125 mL of a liquid (207.5g). What is the density of the liquid?

3. One ton is equal to 2000 pounds, 2.205 pounds = 1 kilogram. A typical rate of deposit of dust ("dustfall") from air that is not significantly polluted might be 3.86 tons per square kilometer per month. What is this dustfall, expressed in milligrams per square meter per month?




My attemps at number 3!

The only one I'm able to do, is the third one.

Here's my work, as best I can write here:

3.86tons/km^2/month x 2000lbs/1ton x 1kg/2.205lbs. x 1000m^2/1km^2 x 1000000mg/1kg

3.86 x 2000 x 1000000 x 1000/2.205

3.501133787 x 10^12 mg/m^2 /month is the answer that I got.

Unfortunately our teacher did not do a very good job teaching us DA...

Thanks for any help,

montagical
 
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Relevant formula you will need is ρ=M/V OR Density=Mass/Volume
 

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