How Do You Calculate the Mass of a Steel I-Beam?

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Homework Help Overview

The problem involves calculating the mass of a steel I-beam with given dimensions and density. The beam's length, height, width, and thickness are specified, leading to questions about how to interpret these measurements in the context of the beam's geometry.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the cross-sectional area of the I-beam but expresses uncertainty about the definitions of height and thickness. They seek clarification on these terms and their implications for the calculation.
  • Some participants provide a visual representation of the I-beam's cross-section to aid understanding and clarify the dimensions involved.
  • There is discussion about the ambiguity of whether the height includes the thickness of the horizontal sections or not, prompting suggestions to make assumptions clear in the calculations.

Discussion Status

Contextual Notes

There is a noted ambiguity in the problem regarding the definitions of height and thickness, which may affect the calculation. The original poster is also uncertain about the equations needed to complete the solution.

CollegeStudent
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Homework Statement


A steel I beam is 6.44 m long, 32.2 cm high and 14.0 cm wide. The top bottom and sides are all 2.00 cm thick. If the density of the steel is 7.56 x 10^3 kg/m^3, find the mass of the beam.


Homework Equations


I'm not sure which equations to use actually.


The Attempt at a Solution


So what I was thinking was

The 2 horizontal parts are 14.0cm * 2.00cm = 28 *2 = 56 cm²
And the 1 vertical part is (32.2cm-4cm) *2cm = 56.4 cm²

So that is 112.4 cm²

Converting this to m² would be .01124m²

After that I'm kind of lost, and I don't even know if THAT'S correct. The thing that's throwing me off is the fact they say there's a length, width, height, and a thickness. Whereas I was taught that thickness and height are the same thing. I don't know how to approach this.

Could someone explain what the difference between height and thickness here...and if I'm on the right track

Thanks everyone
 
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Welcome to PF CollegeStudent!

The reason why there are four dimensions given instead of three is that an I-beam looks like this (like a capital letter I) in cross section):

Code:
              w
-------------------------   
                            t
--------        --------
        |      |
        |      |
        |   t  |  h
        |      |
        |      |
--------        --------
                            t
-------------------------

And "l" is the length of the beam, i.e the distance that this extends "out of your screen." Does that make sense?

EDIT: I attached a screen shot in case that ASCII diagram looks messed up in other browsers.
 

Attachments

  • i_beam.png
    i_beam.png
    719 bytes · Views: 479
One thing that is ambiguous is whether h is the height from the bottom surface of the bottom horizontal section to the top surface of the top horizontal section (i.e. does it include the two thicknesses of those sections), or is it JUST the height of the vertical section, excluding the thicknesses of the horzontal parts. Whatever, just assume something, state explicitly what you assumed, and do the calculation.
 
Your calculation of the cross sectional area looks OK.

Finish the calculation and determine the mass of the beam.
 

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