How Do You Calculate Mechanical Energy Lost Due to Friction on a Slide?

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SUMMARY

The discussion focuses on calculating the mechanical energy lost due to friction for a child sliding down a playground slide. The child has a mass of 27.0 kg and starts from a height of 17.00 m, reaching a height of 7.00 m with a speed of 7.50 m/s. The correct approach involves using the equation W_{FO} = K_2 - K_1 + U_2 - U_1, where K represents kinetic energy and U represents potential energy. The error identified was in the incorrect application of the energy conservation equation, specifically in the order of potential and kinetic energy terms.

PREREQUISITES
  • Understanding of gravitational potential energy (U = mgh)
  • Knowledge of kinetic energy (K = 0.5mv^2)
  • Familiarity with the work-energy principle
  • Basic algebra for manipulating equations
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  • Review the work-energy principle in physics
  • Practice problems involving energy conservation and friction
  • Learn about energy loss due to friction in mechanical systems
  • Explore the concept of non-conservative forces in physics
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bbreezy
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Homework Statement


A 27.0 kg child slides down a long slide in a playground. She starts from rest at a height h1 of 17.00 m. When she is partway down the slide, at a height h2 of 7.00 m, she is moving at a speed of 7.50 m/s. Calculate the mechanical energy lost due to friction (as heat, etc.).


Homework Equations



I used mg(h1)-mg(h2)+.5mv^2

The Attempt at a Solution



I inputted 27(9.81)17-27(9.81)(7) and got 2648.7 and added it to .5(27)(7.5^2) which was 759.375 and came up with the answer 3408.075 J.. this seems to be wrong.. What am I doing wrong here?
 
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bbreezy said:

Homework Statement


A 27.0 kg child slides down a long slide in a playground. She starts from rest at a height h1 of 17.00 m. When she is partway down the slide, at a height h2 of 7.00 m, she is moving at a speed of 7.50 m/s. Calculate the mechanical energy lost due to friction (as heat, etc.).

Homework Equations



I used mg(h1)-mg(h2)+.5mv^2

The Attempt at a Solution



I inputted 27(9.81)17-27(9.81)(7) and got 2648.7 and added it to .5(27)(7.5^2) which was 759.375 and came up with the answer 3408.075 J.. this seems to be wrong.. What am I doing wrong here?
Let K be kinetic energy and U be potential energy. In a perfect world, we have

[tex]K_1 + U_1 = K_2 + U_2[/tex]

But in an imperfect world, there will be a change in the sum of kinetic and potential energy, and a simple way to account for that change is to blame it on friction. Thus,

[tex]W_{FO} = K_2 - K_1 + U_2 - U_1 = \Delta K + \Delta U[/tex]

with W_{FO} being the work of friction done to the object. It will be negative, but your answer should be positive due to the phrasing, so change its sign.

You seem to be doing K_2 - K_1 and U_1 - U_2, causing your error.
 
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