Find the Minimum Initial Acceleration for a Jumbo Jet Takeoff | Homework Help

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Homework Help Overview

The problem involves determining the minimum initial acceleration required for a jumbo jet to take off, given that it must reach a final velocity of 360 km/h while traveling a distance of 1.8 km on the runway. The jet starts from rest and the acceleration is constant.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the kinematic equation and the need for consistent units in calculations. Some express confusion regarding the conversion of units and the implications of starting from rest.

Discussion Status

Some participants have offered guidance on unit consistency and the application of the kinematic equation. There is an ongoing exploration of the relationship between the variables involved, with no explicit consensus reached yet.

Contextual Notes

Participants are addressing the need for unit conversions and the implications of using different measurement systems in the context of the problem.

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Homework Statement



In order for a jumbo jet to take off, it must reach a final velocity of 360 km/h. Given that it moves at a constant acceleration and that the runway is 1.8 km long, find the minimum initial acceleration required to reach the final velocity. The jet starts at rest.

Homework Equations


V1^2 = V0^2 + 2a(x-x0)


The Attempt at a Solution



I tried putting the given values into this equation and nothing sensible happened. The acceleration is constant, so it should be the same at any point. Also, the jet starts at rest, so the velocity at time 0 is 0.

I don't know what's going on, please help

thanks
 
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Everything is to be done in the x coordinate.

360km/h = 100m/s = V(final), distance = 1800m

Given that, and the formula "V1^2 = V0^2 + 2a(x-x0) ", you should be able to find acceleration.

Which should be: 10000 = 0 + 3600a
 
I put the same thing in terms of kilometers and meters, what's the difference?

thanks
 
The units have to be consistent, acceleration = m/(s^2), so when plugging into the formula, length has to be in meters, and time has to be in seconds.
 
ah right. thanks.. I was suspicious of that..

this might sound stupid, but what's the easiest way to convert something into something else?

thanks
 
Last edited:

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