How Do You Calculate Monthly Phone Charges with Long Distance Minutes?

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SUMMARY

The discussion focuses on calculating monthly phone charges for a telephone service that includes a basic local service fee of $29.99 and an additional $4.95 for up to 500 long-distance minutes at a rate of $0.04 per minute. The cost function is defined as C(x) = 29.99 + 4.95 + 0.04x, where x represents the number of long-distance minutes used. For a customer using 345 minutes, the total charge amounts to $48.74. The importance of considering the 500-minute limit in the cost function is emphasized, as exceeding this limit would alter the total charge.

PREREQUISITES
  • Understanding of basic algebraic functions
  • Familiarity with cost function formulation
  • Knowledge of linear equations
  • Ability to evaluate functions at specific values
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  • Research how to incorporate limits in cost functions
  • Learn about piecewise functions for billing scenarios
  • Explore real-world applications of linear equations in pricing models
  • Study the implications of exceeding service limits on billing
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Students studying algebra, financial analysts, and anyone involved in telecommunications pricing strategies will benefit from this discussion.

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Homework Statement



A telephone company charges a fee of $29.99 per month for basic local service. A fee of $4.95 per month is added for customers wanting up to 500 minutes of long distance at $0.04 minute.

a. Write a cost function to determine the amount a customer with the local and long distance plans would be charged that is based on the number of long distance minutes used each month.
b. Use the function you’ve written to determine how much a customer making 345 minutes worth of long distance calls would be charged for the month.




Homework Equations





The Attempt at a Solution



C= p+f+(.04x)
C=29.99+ 4.95+ (.04x)
C=29.99+ 4.95+ (.04x345)
C= 29.99+ 4.95+ 13.80
C= 48.74
Not sure if there needed to be an x after the C or not.
 
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Kristinanne said:

Homework Statement



A telephone company charges a fee of $29.99 per month for basic local service. A fee of $4.95 per month is added for customers wanting up to 500 minutes of long distance at $0.04 minute.

a. Write a cost function to determine the amount a customer with the local and long distance plans would be charged that is based on the number of long distance minutes used each month.
b. Use the function you’ve written to determine how much a customer making 345 minutes worth of long distance calls would be charged for the month.




Homework Equations





The Attempt at a Solution



C= p+f+(.04x)
C=29.99+ 4.95+ (.04x)
This is the answer to part a, except that it doesn't take the limit of 500 minutes into account. For example, by your formula above, a customer who used 1000 minutes would have a bill of 29.99 + 4.95 + .04*1000 = 29.99 + 4.95 + 40 = $74.94.

As I mentioned, this ignores the 500-minute limit. To take that into account, consider the domain for this function.
Kristinanne said:
C=29.99+ 4.95+ (.04x345)
C= 29.99+ 4.95+ 13.80
C= 48.74
Not sure if there needed to be an x after the C or not.
You were asked to come up with a function, so for part a, I would write it like this:
C(x) = 29.99 + 4.95 + .04x, <restrictions on x>
For part b, you are supposed to evaluate your function for x = 345, so you want C(345).
Be sure to include the appropriate units.

BTW, this is not a calculus problem.
 

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