How Do You Calculate Net Resistance and Current Flow in These DC Circuits?

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SUMMARY

The discussion focuses on calculating net resistance and current flow in DC circuits with resistors of 2.9 kΩ. For part a, users confirm that the circuit in Fig 1 can be analyzed using parallel and series equations to find the net resistance. In part b, Ohm's Law (V=IR) is emphasized for calculating total current and its distribution across circuit branches. Part c involves applying Kirchhoff's Rule for circuits with multiple loops, confirming its applicability regardless of the number of loops.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Knowledge of series and parallel resistor combinations
  • Familiarity with Kirchhoff's Circuit Laws
  • Basic circuit analysis techniques
NEXT STEPS
  • Study advanced applications of Kirchhoff's Laws in complex circuits
  • Learn about effective resistance in series and parallel circuits
  • Explore practical examples of current division in electrical circuits
  • Investigate the impact of voltage sources on circuit behavior
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone interested in mastering DC circuit analysis and current flow calculations.

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Homework Statement


http://postimg.org/image/8oweasluj/
Each rectangle in the figures represents a resistor with resistance=2.9kΩ.

a) What is the net resistance of the circuit of Fig 1 connected to the battery? Each resistance has R=2.9 kΩ.

b) What is the current flowing into the junction c and the branch of ca from the battery?

c) If we replace the branch of bc with a 12V battery as Fig 2 shows and Vb>Vc, what is the current flowing into the branch of CA?

The Attempt at a Solution



a) Is the circuit in Fig 1 equal to that of Fig 3 as below?
http://postimg.org/image/t5cwrllzt/

Thank you.
 

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Yes, you can take it and solve it
 
Sumanth said:
Yes, you can take it and solve it

Thank you so much! :D
I know part a then, just apply the parallel and series equations.

But for part b, does it mean that first I have to calculate the total current =It,
then apply Ic=It*(Rt-Rc/Rt), where Rt represents the total resistance?
 
No, just apply ohm's law
 
V=ir. R means effective resistance
"i"means total current through the cell.
And then divide current into the branches of circuit in corresponding ratios.
 
Sumanth said:
V=ir. R means effective resistance
"i"means total current through the cell.
And then divide current into the branches of circuit in corresponding ratios.

I see! I understand now :D Thank you so much!
How about part c then?
Should I use Kirchhoff's Rule? But can Kirchhoff's Rule be applied if there's more than two loops?
 
And in part b, the current flowing into junction c and branch ca would be the same then?
(Since the ratio of resistance are the same?)
 
For part b, can I rather use V=IR to find out the current through branches directly after finding out the total current?
 
Kirchoff law can be applied separately to any number of loops and solve then separately to find currents
 

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