How Do You Calculate Neutron Flux in Neutron Activation Analysis?

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SUMMARY

The discussion focuses on calculating neutron flux in neutron activation analysis, specifically for the production of Na-24 from the irradiation of Al-27. The problem involves determining the total number of Na-24 nuclei present after irradiation and calculating the neutron flux using a reaction cross-section of σ=0.125 barns. Key equations include the rate of neutron absorption R = NσΦ and the decay constant λ. The half-life of Na-22 is provided as 14.951 hours, which is essential for solving the problem.

PREREQUISITES
  • Understanding of neutron activation analysis principles
  • Familiarity with decay constants and half-lives
  • Knowledge of reaction cross-sections in nuclear physics
  • Basic proficiency in solving differential equations related to radioactive decay
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  • Learn about the significance of reaction cross-sections in neutron activation analysis
  • Explore the relationship between decay constants and half-lives in radioactive materials
  • Review differential equations used in nuclear physics applications
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Students in nuclear physics, researchers in radiation safety, and professionals involved in neutron activation analysis will benefit from this discussion.

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Homework Statement

\
(From a past exam paper)
Na-24 can be produced by irradiation of 27-Al with energetic neutrons. It decays by beta emission.

An aluminium sample of mass m=0.2g was irradiated by energetic neutrons for a period of 1 hour. Two hours after the end of irradiation the total 24-Na activity of the sample was 295 Bq.
(i) Calculate the total number of Na-24 nuclei that were present in the aluminium sample immediately at the end of the irradiation.
(ii) What was the neutron flux (use a reaction cross-section of \sigma=0.125 barns).


Homework Equations


Basically, when the sample is being irradiated the number of 24-Na atoms N^{*} obeys
\frac{dN^{*}}{dt} = R - \lambda N^{*}
where R = N\sigma \Phi is the rate of neutron absorption, N is the number of atoms in the sample, \sigma is the microscopic cross-section, and \Phi is the neutron flux. \lambda is the decay constant. Once the irradiation is stopped, it decays according to
\frac{dN^{*}}{dt} = -\lambda N^{*}.

The Attempt at a Solution


It seems to be just a simple plug-and-chug question based on the rudimentary treatment of neutron activation analysis that we did in class, but the thing is that I can't see how you can possibly do it without knowing the Na-24 half-life and the atomic mass of aluminium, and neither of these values were given anywhere in the exam paper. Am I missing something obvious here?
 
Last edited:
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The atomic mass of Al-27 is 27 amu. To go from 27Al to 22Na requires an (n,α) reaction.

The half-life of Na-22 is 14.951 hrs. One reference is http://www.nndc.bnl.gov/chart/.

However, since A = λ N, then is it possible to determine λ, from the information given?
 
Thank you for your answer.
Astronuc said:
The atomic mass of Al-27 is 27 amu. To go from 27Al to 22Na requires an (n,α) reaction.
You're right, I didn't realize that the mass defects are so small that you can just ignore them for these purposes.
The half-life of Na-22 is 14.951 hrs. One reference is http://www.nndc.bnl.gov/chart/.
But the point is, this question was in a past exam paper. That reference would not have been available.
However, since A = λ N, then is it possible to determine λ, from the information given?
But we don't know N either, since the neutron flux is unknown.
 

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