How Do You Calculate Power Absorbed by a Resistor in a Circuit?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the power absorbed by a 15 ohm resistor in a circuit, utilizing principles from circuit analysis such as Kirchhoff's Current Law (KCL), Kirchhoff's Voltage Law (KVL), and Ohm's Law.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the power by first determining the total resistance in a branch and then applying KCL to find current relationships. They express confusion regarding discrepancies between their calculations and the answer key.

Discussion Status

Some participants provide feedback on the original poster's calculations, suggesting a potential miscalculation. There is an ongoing exploration of the validity of the answer key, with some participants questioning its correctness based on their own calculations.

Contextual Notes

Participants are discussing the implications of potentially incorrect information from the answer key, which is influencing their confidence in their own methods and calculations.

homo-sapiens
Messages
28
Reaction score
0

Homework Statement


Determine the power absorbed by the 15 ohms resistor, see circuit below.(the ix, i1, and i2 are things i added)
http://puu.sh/bQyEk/5f47888b03.png

2. Homework Equations

the KCL law
the KVL law
the ohm's law
power = voltage * current

The Attempt at a Solution


I calculated the whole resistance of the second branch first. then I found the relationship between current ix and current i since the voltage of a loop = zero. I then calculated the current using the KCL current law. i then found a relationship between current i1 and current i2. I calculated current i2 and used the power = resistance * current * current.
My answer is way off from the answer key, and I would like to know what I did wrong??

http://puu.sh/bQyK1/715544a6a1.png
 
Last edited by a moderator:
Physics news on Phys.org
Your approach looks good. It looks like you miscalculated ix = 36/51*(.425).
 
ops! that was a minor mistake on my part, but the answer is still not right with the answer key...
here is the answer key
http://puu.sh/bQDw6/e03756b3b0.jpg
 
Last edited by a moderator:
The answer key is wrong. It comes up with v = -19 when solving for -2 - 2*v/6 = v/8.5 + v/6 + v/6, which is clearly incorrect (I calculate v = -2.55).
 
OH! thank you so much for clearing this up for me. aw, never thought the answer key would be wrong. I guess I should believe in my methods more often. thank you again.
 
You're welcome! It's always unnerving when the answer key is wrong, but it's nice when you can spot the mistake so you know for sure.
 

Similar threads

Replies
16
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
22
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K