How Do You Calculate Pressure of Helium in Different Conditions?

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SUMMARY

The pressure of 0.3000 moles of helium (He) in a 0.2000L container at -25.0°C can be calculated using two methods: the Ideal Gas Law and van der Waals equation. The Ideal Gas Law (PV = nRT) yields a pressure of approximately 2.83 atm when R = 0.0821 L·atm/(K·mol). In contrast, applying van der Waals equation with parameters a = 0.0341 atm·L²/mol² and b = 0.0237 L·mol results in a corrected pressure value that accounts for intermolecular forces and molecular volume.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Familiarity with van der Waals equation (P + a(n/V)²)(V - nb) = nRT
  • Basic knowledge of gas properties and behavior
  • Ability to perform unit conversions and calculations
NEXT STEPS
  • Study the Ideal Gas Law and its applications in real-world scenarios
  • Explore the derivation and implications of van der Waals equation
  • Learn about the differences between ideal and real gases
  • Investigate other gas laws such as Boyle's Law and Charles's Law
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Students in chemistry, physics enthusiasts, and professionals in fields requiring gas behavior analysis, particularly those studying thermodynamics and physical chemistry.

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Calculate the pressure exerted by 0.3000 mole of He in 0.2000L container at -25.0^o C

a) Using the ideal gas law
b) Using van der Waal's equation (a=0.0341 atmL^2/mol^2 and b = 0.0237 Lmol)

i have no idea how to do this problem?? please helppp
 
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Start by writing down the two gas laws you are given. Try to understand what the variables in those equations mean and what variables you are given.
 

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