How Do You Calculate Resultant Displacement for Two Interfering Waves?

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To calculate the resultant displacement of two interfering waves, it's essential to recognize their phase relationship. The waves y1 and y2 are out of phase, which affects their superposition. Instead of simply adding the wave functions, one should evaluate each wave at the given time t = 6.0 s and then sum the results. The correct approach involves resolving the cosine terms and understanding that one wave's phase shift leads to destructive interference. Ultimately, the resultant displacement at t = 6.0 s is -1.0 m.
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Homework Statement



Two displacement waves with the same period T = 3.0 s are described mathematically by:

y1 = (10.0 m) cos[2πt/T + π]
y2 = (9.0 m) cos[2πt/T + 2π]

What is the resultant displacement at time t = 6.0 s?

The Attempt at a Solution



I tried adding up

y1 + y2 = 19 cos [2πt/T + 3π]

But the answer I get is wrong. I also tried the following formula from my texybook which is supposed to give the resultant of two traveling sinusoidal waves:

y=2Acos \left( \frac{\phi}{2} \right) sin \left( kx-\omega t + \frac{\phi}{2} \right)

I don't know what the phase constant (φ) is, so I assume it is zero since the waves are in phase, then cos(φ/2)=cos(0)=1.

When I plug in the numbers the formula then becomes

y=6sin(3π+2π6/3)

Again, this produces the wrong answer, the correct answer should be -1.0 m. What's wrong with my calculations? :confused:
 
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roam said:

Homework Statement



Two displacement waves with the same period T = 3.0 s are described mathematically by:

y1 = (10.0 m) cos[2πt/T + π]
y2 = (9.0 m) cos[2πt/T + 2π]

What is the resultant displacement at time t = 6.0 s?

The Attempt at a Solution



I tried adding up

y1 + y2 = 19 cos [2πt/T + 3π]

:


You can not do that! Try to think instead of plugging into equations you do not understand.

Resolve the cosine terms. What is the relation between cos(x) and cos(x+2π)? between cos(x) and cos(x+π)?


ehild
 


ehild said:
You can not do that! Try to think instead of plugging into equations you do not understand.

Resolve the cosine terms. What is the relation between cos(x) and cos(x+2π)? between cos(x) and cos(x+π)?


ehild

Does this mean that they are out of phase? I think if one wave has phase constant φ=(2N)π and the other wave has φ=(2N+1)π, where N is any integer, then the two waves are not in phase, and therefore destructive interference occurs.

What do you mean by "resolving" the cosine terms? :rolleyes:

The "superposition principal" states that the resultant value of the wave functions of the wave function at any point is the algebraic sum of the values of the wave functions of the individual waves. This is what I was trying to do, in my problem do I need to somehow subtract thw two given wave functions?
 


roam said:
What do you mean by "resolving" the cosine terms? :rolleyes:

Well, my English is poor, especially in maths expressions. I meant to express both cos[2πt/T + π] and cos[2πt/T + 2π] with cos (2πt/T). Think of the definition of the cosine function.

And you are right, y1 and y2 are out of phase.

If you still do not get it, just plug in 6.0 s for t, calculate both y1 and y2 and add them.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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